Can someone me with this and show the work

The vertex form is: y =  3(x-2)^2 + 7 . The vertex is (2, 7)

Step-by-step explanation:

Write the function: y = 3x^2 - 12x + 11 in vertex form

The vertex form of a quadratic equation is:

y = m(x - a)^2 + b where (a,b) is the vertex

For y = 3x^2 - 12x + 11

Solve for m

y = 3(x^2 - 4x) + 11

Complete the Square:

y = 3(x^2 - 4x + 4) + 11 - 4

y = 3(x - 2)^2 + 7

The vertex then is (2, 7)

the vertex (-2, -1)

Step-by-step explanation:

y = 3x² + 12x + 11

Rewrite the equation in vertex form.

3(x + 2)² - 1

set y equal to the new right side

y = 3(x + 2)² - 1

Use the vertex form, y = a(x-h)² + k

a = 3

h = -2

k = -1

therefore,

the vertex (-2, -1)

56

step-by-step explanation:

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