Aci is desired for the true average stray-load loss μ (watts) for a certain type of induction motor when the line current is held at 10 amps for a speed of 1500 rpm. assume that stray-load loss is normally distributed with σ = 2.1. (round your answers to two decimal places.)

(a) compute a 95% ci for μ when n = 25 and sample mean = 58.3.
(b) compute a 95% ci for μ when n = 100 and sample mean = 58.3.

Step-by-step explanation:

Given that X stray load loss is normal with population std dev = 2.1

Since population std deviation is known we can use Z critical values for finding out confidence intervals

For 95% confidence interval we have formula as

Confidence interval 95% =

a) Substitute here for x bar = 58.3 and sigma = 2.1,n=25

Confidence interval =

b) NOw we substitute sample size n =100, for same mean and std dev.

Confidence interval =

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: