The attractive electric force between point charges q and -2q has a magnitude of 2.2 n when the separation
between the charges is 1.4 meters. what is the magnitude of charge q?

The Magnitude of charge = q = 15.47 micro coulomb  

Step-by-step explanation:

The attractive force between two points q and - 2 q = F = 2.2 Newton

The separation between two charges = 1.4 meters

Now from Coulomb's law = F =  where k=

So , 2.2 = (

So , q ² = ()

      For charge magnitude

   I.e q ² =

 so, q =  

      q = 15.47 \times 10^{-6} c

Or,  q = 15.47 micro coulomb

Hence  the Magnitude of charge = q = 15.47 micro coulomb   Answer