33. suppose you were on a planet where the
acceleration of gravity was only 2.0 m/s2 instead
of 9.8 m/s2 as on earth. (a) estimate the height
to which you could jump vertically from a
standing start if you can jump to 0.75 m on
earth. (b) how high could you throw a baseball
if you could throw it 18 meters up on earth?

a) 3.675 m  

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth =

And on planet given =

A) Since the maximum jump height is given by the formula  

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0 and  

g2 = 9.8

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by  

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0  and g2 = 9.8

We get h1 = 3.67m which is the required height

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.