Can someone solve these simultaneous equations?
a.) 2^x+y=8
3^2x-y=27
b.) 3^y+x=9^y+x
2^x-y=8^x-3

a) x = 2, y = 1

b) x = 9, y = -9

Step-by-step explanation:

a)    

   ⇒

   ⇒

and

  ⇒

  ⇒

By solving the above two equations, we get;

x = 2 and y = 1

b)    

   ⇒

   ⇒

and

   ⇒

   ⇒

By solving the above two equations, we get;

x = 9 and y = -9

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2