9times a number has 1 subtracted from it. the result is trebled. the answer is the same if you add 7 to twice the number and multiply the result by 7. what is the number?

4

Step-by-step explanation: 1) You need to first understand the question and a way to do that is to list plainly the information given.

2) Let the number be (X)

3) For the equation from the first sentence given; 3(9x-1)

4) From the second sentence; 7(7+2x)

5) Equating both sentences together, since the question says they are the same 3(9x-1) = 7(7+2x)

6) Opening the bracket/expanding the equation 27x-3=49+14x

Solving further we will have 13x = 52

X= 52/13

= 4

The number is 4.

Step-by-step explanation:

Let the number =x.

9 times a number has 1 subtracted from it =9x-1

The result is trebled=3(9x-1).

The answer is the same if you add 7 to twice the number and multiply the result by 7= (7+2x)7.

Now, 3(9x-1)=7(7+2x)

Opening the brackets, 27x-3=49+14x

Collecting like terms, 27x-14x=49+3

Hence, 13x=50

Dividing both sides by 13, we have x=4.

Therefore, the number is 4.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116