Police records in the town of saratoga show that 17 percent of the drivers stopped for speeding have invalid licenses. if 24 drivers are stopped for speeding. (a) find the probability that none will have an invalid license. (round your answer to 4 decimal places.) probability (b) find the probability that exactly one will have an invalid license. (round your answer to 4 decimal places.) probability (c) find the probability that at least 2 will have invalid licenses. (round your answer to 4 decimal places.) probability

Step-by-step explanation:

Given

17 % of the drivers stopped have invalid licenses

n=24 drivers are stopped

using Binomial distribution

here p=0.17

q=1-0.17=0.83

(a)none will have valid license i.e. r=0

(b)Exactly one have invalid license i.e. r=1

(c)At least 2 will have invalid license i.e.

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b