In a class of 40 students, everyone has either a pierced nose or a pierced ear. the professor asks everyone with a pierced nose to raise his or her hand. seven hands go up. then the professor asked everyone with a pierced ear to do likewise. this time there are 36 hands raised. how many students have piercings both on their ears and their noses? i would think the obvious answer could be 7 but not necessarily. can anyone me with this formula?

3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

where Students either nose or ear Pierced

no of students having both nose and ear pierced

answer:   rlly

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet