Due: 10-31-2019
triangle pqr is transformed to triangle p′q′r′. triangle pqr has vertices p(8, 0), q(6, 2), and r(−2, −4). triangle p′q′r′ has vertices p′(4, 0), q′(3, 1), and r′(−1, −2). plot triangles pqr and p′q′r′ on your own coordinate grid.

part a: what is the scale factor of the dilation that transforms triangle pqr to triangle p′q′r′? explain your answer. (4 points)
part b: write the coordinates of triangle p′′q′′r′′ obtained after p′q′r′ is reflected about the y-axis. (4 points)
part c: are the two triangles pqr and p′'q′'r′' congruent? explain your answer.

Here's what I get  

Step-by-step explanation:

I plotted the triangles in the diagram below.

Part A

The scale factor for dilation is ½, because every coordinate has been halved.

  P (8, 0) ⟶ P' (4, 0)

  Q (6, 2) ⟶ Q' (3, 1)

R (-2, -4) ⟶ R' (-1, -2)

Part B

When you reflect a point (x, y) about the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

  P' (4,0) ⟶ P" (-4,0)

Q' (3,-1) ⟶ Q" (-3,-1)

R' (-1,-2) ⟶ R" (1,-2)

∆P"Q"R" has coordinates P" (-4,0), Q" (-3,-1), R"(1,-2).

Part C

∆PQR and ∆ P"Q"R" are not congruent, because corresponding sides are not equal.

answer: idk

step-by-step explanation:

addition

step-by-step explanation: