How do i divide a 6 and 3/4 inch line into three parts so that each part is 1/4 inch shorter than the others before it

  2 1/2, 2 1/4, 2

Step-by-step explanation:

Let x represent the first part. Then the next part is (x -1/4), one-quarter inch shorter. The part after that is ((x -1/4) -1/4), one-quarter inch shorter still.

The sum of these three parts is 6 3/4:

  x + (x -1/4) + (x -1/2) = 6 3/4

  3x -3/4 = 6 3/4 . . . . . . . . . . . . collect terms

  x -1/4 = 2 1/4 . . . . . . . . . . . . . . divide by 3

  x = 2 1/2 . . . . . . . . . . . . . . . . . add 1/4

So, the first piece is 2 1/2; the next piece is 1/4 shorter, so is 2 1/4; and the last piece is 1/4 shorter still, so is 2 inches.

The pieces are 2 1/2 inches, 2 1/4 inches, and 2 inches long.

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}