Question 1 what is −12÷2/3
question 2 what is -8/3÷7/12
question 3 divide.8.64÷(−0.27)
question 4 starting at sea level, a submarine descended at a constant rate to a depth of −3/4 mile relative to sea level in 5 minutes. what was the submarine's depth relative to sea level after the first minute?
enter your answer in a fraction in simplest form.
question 5 one cold night the temperature was 0 degrees at 8 p. m. the temperature dropped at a constant rate from 8 p. m. to midnight. at midnight the temperature was −16.8 degrees.
what was the temperature at 9 p. m.?

Step-by-step explanation:

1) −12÷2/3  = -12 * 3/2 = -6*3 = -18

2) -8/3÷7/12 = -8/3 * 12/7 = -8*12 / 3*7 = -96/21

3)8.64÷(−0.27) = 8.64/-0.27 = 8.64*100/-0.27*100 =864/-27 = - 32

4) The submarine's depth relative to sea level after the first minute = -3/4 divided by 5

= -3/4 *1/5 =-3/20 = -0.15 miles

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)