What is the solution of the linear-quadratic system of equations?

{y=x^2+5x−3
{y-x=2

the above stated equation is a quadratic equation

Step-by-step explanation:

Given the following equations

y = x^2 + 5x - 3equation 1

y-x = 2

y = x + 2equation 2

Let equation 1 equal equation 2

x^2 + 5x -3 = x + 2

Bringing the equation to one side and equating to zero

X^2 +5x - 3 -x -2 = 0

X2 + 5x -x -3 -2 = 0

X^2 + 4x -5

Solving the aquatic equation

(x + 5)(x -1) = 0

X + 5 = 0

X1 = -5

X- 1 = 0

X2 = 1

To prove:

Substitute the values for x1and x2 into the equation x^2 + 4x - 5 = 0

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .

i belive the biggest ratio would be 18: correct me if im wrong