2i^4−5i^3+3i^2+√−81 rewritten in a+bi form?

-1 + 14i.

Step-by-step explanation:

i^2 = -1.

i^4 = i^2 * i^2

= -1 * -1 = 1.

i^3 = i^2 * i = -i.

√−81 = i√81 = 9i.

So

2i^4−5i^3+3i^2+√−81

= 2 - (5 * -i)  - 3 + 9i

= -1 + 5i + 9i

= -1 + 14i.

for the points! : )