In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsible for long-term memory storage, in adolescents. the researchers randomly selected 13 adolescents with alcohol use disorders to determine whether the hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm cubed. an analysis of the sample data revealed that the hippocampal volume is approximately normal with x overbarequals8.12 cm cubed and sequals0.8 cm cubed. conduct the appropriate test at the alphaequals0.01 level of significance.

The hippocampus volumes in the alcoholic adolescents are less than the normal volume of 9.02 cm³

Step-by-step explanation:

Let x= the hippocampus volumes in the alcoholic adolescents

We'll conduct a hypothesis test at the 0.01 significance level with

Null hypothesis: x = 9.02 cm³

Alternate hypothesis: x < 9.02 cm³

A sample of 13 alcoholic adolescents gives the parameters

size=N= 13

mean=M= 8.12 cm³

standard deviation= s= 0.8 cm³

According to the sample, with 99% confidence, t statistic for the value X=9.02 can be found using the formula:

t= where

If we put these numbers in the formula:

t= =4.056

One tailed critical value for the sample with 12 degrees of freedom (sample size-1) in 99% confidence level is 2.681.

Since t value (4.056) is bigger than the critical value, we fail to reject the alternate hypothesis, therefore reject the null hypothesis and accept alternate hypothesis.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

there are no answer choices

step-by-step explanation: