Jean stocked her aquarium with 36 fresh-water fish, which cost $212. the male fish cost $5 each, while the female fish cost $7 each. find the number of male fish (x) and the number of female fish (y).

Male Fish = 20

Female Fish = 16

Step-by-step explanation:

Let number of male fish be x and number of female fish be y

There are 36 fishes in total, so we can write:

x + y = 36

or

x = 36 - y

Also, male fish (x) cost 5 each and female fish (y) cost 7 each totalling $212, so we can write:

5x + 7y = 212

Now, we can put 1st equation in 2nd equation and get an equation in "y" and solve for y first:

We know x = 36 - y, so

x = 36 - 16

x = 20

Thus,

there are

20 Male fishes & 16 female fishes in the aquarium

x= cost per bracelet

number of bracelets * x + shipping charge = total cost

so

9x+9=72

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%