Timed question need fastwhat values of b satisfy 3(2b + 3)2 = 36?

a. b = startfraction negative 3 + 2 startroot 3 endroot over 2 endfraction andstartfraction negative 3 minus 2 startroot 3 endroot over 2 endfraction
b. b = startfraction negative 3 + 2 startroot 3 endroot over 2 endfraction and startfraction negative 3 minus 2 startroot 3 endroot over 2 endfraction
c. b = startfraction 3 over 2 endfraction and startfraction negative 9 over 2 endfraction
d. b = start fraction 9 over 2 endfraction and startfraction negative 3 over 2 endfraction

Step-by-step explanation:

Taking square root both sides, we get

Therefore, the values of are:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3