Find two consecutive odd integers such that 32 more than the lesser is three times the greater

First odd number  = 13

Second odd number  = 15

Step-by-step explanation:

Let

First odd number  = 2x + 1

Second odd number = 2x + 3

According to given conditions:

32 + 2x + 1= 3 (2x + 3)

33 + 2x = 6x + 9

Taking terms with x to left and constants to right

2x - 6x = 9 - 33      (sign of transferred terms will be changed)

-4x = -24    

Dividing both sides by -4

x = -24/-4

x =6

So,

First odd number  = 2x + 1 =  2*6 + 1 = 12 + 1 =13

Second odd number = 2x + 3= 2*6 +3= 12 + 3 = 15

I hope it will help you!

step-by-step explanation:

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