Jamie invested $3000, part at 11% interest in a porridge company and part at 8% in a bowl company. she earned $216 more in interest from the 11% investment than she did from the 8% investment. how much did she invest at each rate?

Step-by-step explanation:

Let x represent the amount invested at 11%. Then (3000-x) is the amount invested at 8%. The interest difference is ...

  0.11x - 0.08(3000 -x) = 216

  0.19x -240 = 216 . . . . . . . . simplify

  0.19x = 456 . . . . . . . . . . . . add 240

  456/0.19 = x = 2400 . . . . . the amount invested at 11%

  3000-2400 = 600 . . . . . . . the amount invested at 8%

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

3

step-by-step explanation: