If the equation of a circle is (x - 2)2 + (y-6)2 = 4, it passes through point
, 6)
b.(4,6)
c.(2,6)
d.(2,-6)

(x - 2)² + (y - 6)² = 4

You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point

Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)

So alternative b.

To be more certain just subs the point in the x and y, if its equal, it pass through

(x - 2)² + (y - 6)² = 4

To point (4, 6)

(4 - 2)² + (6 - 6)² = 4

(2²) + 0² = 4

4 = 4

Thats right

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

i will pick c put check it over to be sure

step-by-step explanation: