Amachine at k& a tube & manufacturing company produces a certain copper tubing component in a refrigeration unit. the tubing components produced by the manufacturer have a mean diameter of 0.75 inch with a standard deviation of 0.004 inch. the quality-control inspector takes a random sample of 30 components once each week and calculates the mean diameter of these components. if the mean is either less than 0.748 inch or greater than 0.752 inch, the inspector concludes that the machine needs an adjustment. (a) what is the sampling distribution of the sample mean diameter for a random sample of 30 such components? justify your answer. (b) what is the probability that, based on a random sample of 30 such components, the inspector will conclude that the machine needs an adjustment?

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step-by-step explanation:

sdfghjkl; vbnm,

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: