Asquare has a perimeter of 36 inches. find the length of the diagonal in simplest radical form.

Step-by-step explanation:

step 1

Find out the length side of the square

we know that

The perimeter pf the square is equal to

where

b is the length side of the square

we have

so

Solve for b

step 2

Find out the length of the diagonal applying the Pythagoras Theorem

Let

D -----> the length of the diagonal of the square

b ----> the length side of the square

we have that

we have

substitute

Simplify

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

just took the test and my answers down below!

step-by-step explanation:

check the pic :