U1995, 70% of all children in the u. s. were living with both parents. if 25 children were selected at random in the u. s., what is the probability that at most 10 of them will be living with both of their parents? round your answer to 4 decimal places. to answer the question input only the actual number. do not include units. do not give your answer in sentence form -- just include the numerical answer rounded to exactly 4 decimal places.

The probability that at most 10 of them will be living with both of their parents is 0.0018

Solution:

Given, US 1995, 70% of all children in the U.S. were living with both parents.  25 children were selected at random in the U.S.,  

We have to find what is the probability that at most 10 of them will be living with both of their parents?  

Now, number of children picked (n) = 25.

Probability to be with parents = 70% = 0.7.

Our condition is 0 ≤ x ≤ 10.

Then, we have to calculate p(0 ≤ x ≤ 10).

We can calculate using binomial cumulative distribution frequency- binomial CDF

Now, p(0 ≤ x ≤ 10) = binomcdf(n, p, x) = binomcdf(25, 0.7, 10) = 0.00177840 ≈ 0.0018.

Hence, the probability is 0.0018

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .