4. the population of bay village is 35,000 today. every year the
population of bay village increases by 750 people.
a. write a linear model that represents the population of bay
village x years from today

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle Linear Models are employed when we want to define a relationship between an independent and a dependent variable. Linear Models are also known as Functions , where one variable is expressed as a function of at least one other variable. The most common example would be a dependent variable that is directly linked as a response to any changes of an independent variable . The most common expression of such relationship would be where is the relationship factor between and and is also known as the slope of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  .

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call and our fixed factor is the 750 increment which we will call .  

From that we can conclude that:

Year 1 Population: 35,000

Year 2 Population: 35,000 + 750 = 35,750

Year 3 Population: 35,750 + 750 = 36,500

And so on and so forth.

So we want to express the above as a Linear Model of the form:

  Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

Which for every different value of   (i.e. every year) we can obtain the new and increased population  .

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

c(x)= 6x + 3

step-by-step explanation: