When ax^2 + bx - 1 is added to ax^3 + 2bx^2 - 2x -1, the result is 3x^3 + 11x^2 + 2x -c. find a, b, and c

the answer is 5/3x+7/5y+7

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)