An experiment consists of tossing a penny, a nickel and a dime. of interest is the side the coin lands on.

(a) how many elements are there in the sample space?

(b) let a be the event that there is at least one head and at least one tail. p(a) = round your answer to two decimal places.

(c) let b be the event that the first and second tosses land on tails. are the events a and b mutually exclusive? (yes or no)

Part (A) There are 8 elements in the sample space.

Part (B) The required probability is

Part (C) Yes, the events A and B mutually exclusive.

Step-by-step explanation:

Consider the provided information.

An experiment consists of tossing a penny, a nickel and a dime. Of interest is the side the coin lands on.

Part (a) How many elements are there in the sample space?

We are interested in the side of the coin lands,

a coin has two side, one is head and another is tail.

So the sample space of tossing 3 coins is:

(H,H,H), (H,H,T), (H,T,H), (T,H,H), (T,T,H), (T,H,T), (H,T,T), (T,T,T)

Hence, there are 8 elements in the sample space.

Part (b)  Let A be the event that there is at least one head and at least one tail. P(A) = Round your answer to two decimal places.

If A is the event that at least one head and at least one tail then the number of possible outcomes are: (H,H,T), (H,T,H), (T,H,H), (T,T,H), (T,H,T), (H,T,T)

Therefore the favorable outcomes are 6 and total number of outcomes are 8.

Hence. the required probability is

Part (c) Let B be the event that the first and second tosses land on tails. Are the events A and B mutually exclusive? (yes or no)

The event is said to be mutually exclusive if P(A∩B)=0 or we can say that there is no common outcomes.

Since, event A and B can't happen at the same time, that means it is not possible to obtained 2 tails if the event A occurs.

Therefore P(A∩B)=0

Hence, the events A and B mutually exclusive.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer: 88

step-by-step explanation: