Claude uses the greatest common factor and the distributive property to rewrite this sum 45+90 drag one number to each box to show claudes expression

Hello mate!

The boxes are missing, but let's solve it in the most general way:

our sum is:

45 + 90

and we want to rewrite it with the greater common factor and the distributive property.

First, let's find the greatest common factor.

The first thing is taking the smaller number, and check if the divisors of this number (from greatest to smallest) and see if they divide the other number, the biggest divisor that divides both numbers is the greatest common factor.

Now the smallest number is 45, and the biggest divisor of 45 is the same number because 45/45 = 1

let's check if 45 also divides 90.

90/45 = 2

Then 45 is the greatest common factor between 90 and 45.

We also know that 45 = 45*1, and 90 = 45*2

now let's rewrite our sum:

45 + 90 = 45*1 + 45*2

now we can use the distributive property:

45*1 + 45*2 = 45*( 1 +2)

then:

45 + 90 = 45*( 1 + 2) = 45*3

This should be Claude's expression.

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