Find the area of the surface. the part of the plane 2x + 13y + z = 26 that lies in the first octant

Surface Integral

Step-by-step explanation:

If the surface is defined as , then integrating the area of one patch over the whole domain D will give the surface area.

In this case we can write:

To see where the plane intersects the first octant, look for the intercepts with the x, y and z axes:

(2,0,0),(0,13,0)(0,0,26)

So the domain D is the triangle in the first quadrant of the xy plane bounded by (0,0) (2,0) and (0,13). We could compute this using geometry:

idk

step-by-step explanation:

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.