Kara had a savings account balance of $153 on monday on tuesday she has six withdrawals of $15.72 and a deposit of $235.15 what was her account balance after these transactions

$293.83

Step-by-step explanation:

She started with $153. The next day she withdrew $15.72 six times, that is $15.72*6 = $94.32

We have to subtract $94.32 from the starting amount, that is $153 - $94.32 = $58.68

After that, she deposited $235.15. We have to add that to the current balance.

Now she has $58.68 + $235.15 = $293.83

Therefore, her account balance after these transactions is $293.83

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.