You invested $21,000 in two accounts paying 2% and 4% annual interest, respectively.
if the total interest earned for the year was $660, how much was invested at each rate?
the amount invested at 2% is $

Step-by-step explanation:

If x represents the amount invested at 4%, then the total interest earned is ...

  0.04x + 0.02(21000 -x) = 660

  0.02x = 240 . . . . . . . . . . . simplify, subtract 420

  x= 240/0.02 = 12,000 . . . . amount invested at 4%

  21,000 -x = 9,000 . . . . . . . . amount invested at 2%

The amount invested at 2% is $9,000.

The amount invested at 4% is $12,000.

Comment on method of solution

These problems can usually be solved using one variable for the amount associated with the highest contribution to the mix. Here, that is the amount getting 4% interest. This keeps the numbers in the solution positive, helping to minimize errors. As you can see, the solution develops in about 2 or 3 steps. Other methods can take longer.

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.