Terminal velocity is the fastest speed that an object can fall through the air. a skydiver reaches a terminal velocity of 120 miles per hour. what is the change in elevation of the skydiver after falling at terminal velocity for 15 seconds?

146.7 m

Step-by-step explanation:

Data:

Let the terminal velocity, be  = 120 miles/h

                                                   =  53. 6448 m/s

The time taken for the fall, t      = 15 sec

Let, the initial velocity, u = 0

Therefore, the equation to calculate distance will be:

where a = g = 9.81

           s = distance traveled

Therefore:

2877.76 = 19.62s

         s = 146.7 m

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.