You just got a free ticket for a boat ride, and you can bring along 3 friends! unfortunately, you have 6 friends who want to come along.
how many different groups of friends could you take with you?

Assuming that your own ticket is already secured.

From the 5 friends you can only choose 3.

The order in which these friends are chosen is not relevant. So this is a Combination problem.

Where the order is relevant the problem becomes a Permutation problem! 

So the answer is 5 combination 3.          =  ⁵C₃

⁵C₃  =  (5 * 4 * 3) / ( 3 * 2 * 1) = 20

You can take 10 groups of any 3 of your 6 friends.

Hope this helps! have a spooky day!

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. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: