Find the 30th term of an arithmetic progression 5,1015,20

150

Step-by-step explanation:

The n th term of an arithmetic progression is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here d = 10 - 5 = 5 and a₁ = 5, hence

= 5 + (29 × 5) = 5 + 145 = 150

is there a picture

step-by-step explanation:

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6