Amodel rocket is launched with an initial velocity of 250 ft per second. the height h, in feet, of the rocket t seconds after launch is given by h=-16t^2+250t. how many seconds after the launch will the rocket be 450 ft above the ground

17

step-by-step explanation:

7,24

step-by-step explanation:

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368

question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)