Suppose an airplane is flying 11,000 feet above the ground. another plane is directly above at 35,000 feet above the ground. how far apart are the airplanes?

24, 000 feet

Step-by-step explanation:

If plane 1 is flying at 11,000 feet and plane 2 is flying at 35, 000 feet from the ground which is a common reference point for both planes, the the formula for calculating how far the planes are would be:

Distance between planes= (Elevation of Plane 2-Elevation of Plane 1 )

(350000-11000)= 24,000 feet

This means that Plane 2 is 24,000 feet above Plane 1

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18