The length of a standard jewel case is 7cm more than its width. the area of the rectangular top of the case is 294 cm^2. find the length and width of the jewel case.

Length = 21 cm

Width = 14 cm

Step-by-step explanation:

Let the width of the jewel case = m cm

So, the length of the case = (m + 7) cm

Area of the case =

Now, Area of a Rectangle = Length x Width

=   m x (m + 7)

⇒  m x (m + 7) = 294

or,

⇒  

or,

⇒(m + 21)(m -14) = 0

Hence, either (m + 21) = 0  ⇒ m  = -21

or, (m -14) = 0⇒ m = 14

Since, m is the width of a case, so it can not be negative

Hence the width of the jewel case = m = 14 cm

And the length of the case = (m + 7) = 14 + 7 = 21 cm

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )