A25.0 g sample of garden compost was analyzed for chloride content. the sample was dissolved in water and the chloride was precipitated as silver chloride. 1.58 g of dried precipitate was obtained. calculate the percent chloride in the sample.

The percent chloride in the sample is 1.56%

Step-by-step explanation:

Hi there!

The molecular formula of silver chloride is AgCl. Its molar mass (the mass of a mol of AgCl) is 143.32 g/mol. Then the number of moles of AgCl obtained in the precipitated will be:

1.58 g · (1 mol/143.32 g) = 0.0110 mol

Then, since 1 mol AgCl contains 1 mol Cl⁻ (chloride), in the sample of compost there will be 0.0110 mol Cl⁻.

The mass of 0.0110 mol Cl⁻ is:

0.0110 mol Cl⁻ · (35.453 g /mol) = 0.390 g Chloride.

Then, the percent chloride in the sample will be:

0.390 g · (100 % / 25.0 g) = 1.56%

The percent chloride in the sample is 1.56%

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.