Find the equation of a line which passes through the point (3, -1) with the gradient m=2÷3

Step-by-step explanation:

Equ of line -

y=mx+c

Using point (3,-1)

3 as x, - 1 as y

M=2/3

Substitute the values of these coordinates

3=2/3(-1) +c - - - - now find for c

c= 3- (-2/3)

c= 3.67

Now with the value of c, put the values back into the equation form .. Assuming we don't have a point to work with

y=2/3x + 3.67

hope this .

r3t40

the answer is c. 23/3