Mathematics, 25.10.2019 04:43, mtmtcow1122

Arectangle has an area of 12y^2+21y^512 y 2 +21y 5 12, y, squared, plus, 21, y, start superscript, 5, end superscript. the width of the rectangle is equal to the greatest common monomial factor of 12y^212y 2 12, y, squared and 21y^521 y 5 21, y, start superscript, 5, end superscript. what is the length and width of the rectangle?

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Arectangle has an area of 12y^2+21y^512 y 2 +21y 5 12, y, squared, plus, 21, y, start superscript, 5...