Amass of 100 g stretches a spring 5 cm. if the mass is set in motion from its equilibrium position with a downward velocity of 70 cm/s, and if there is no damping, determine the position u of the mass at any time t. (use g = 9.8 m/s2 for the acceleration due to gravity. let u(t), measured positive downward, denote the displacement in meters of the mass from its equilibrium position at time t seconds.) *differential equation

what does u(t) equal?

when does the mass first return to its equilibrium position? (what does t in seconds equal? )

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation:

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

sorry man i accidentally pressed yes my bad

step-by-step explanation: