If the equation of a line has an undefined slope and passes through the point (1, 3), which form would be used to write the equation of the line

Another version you can use is slope-intercept form.   The two above are standard and point-slope forms. First you do need to find the slope of the line based on m=(y2-y1)/(x2-x1) so for these points: (0,3) and (2,0) --> (x1, y1) and (x2, y2)x1=0y1=3x2=2y2=0 m= (0-3)/(2-0) = -3/2 Then your formula will need to look like y=mx+b where b is your y-intercept (when x=0)  Due to have the x=0 point, you are pretty much done: y=-3/2*x+3 If you do not have a (0,y) form, you can solve as follows:Write out the formula with your slope value inserted:y=-3/2*x+b Choose one of your points on your line to solve for b.  I choose (2,0):0=-3/2*2+b0=-3*1+b3=b --> b=3 

Hi Freedom;(0,3) (2,0)Slope is change-of-y divided by change-of-x...m=(y-y1)/(x-x1)m=(3-0)/(0-2)m=3/-2=-3/2Slope-intercept format is...y=mx+bm is the slope.b is the y-intercept, the value of y when x=0.y=(-3/2)x+bThe y intercept is provided as (0,3)...y=(-3/2)x+3 

(0,3) & (2,0) are the y and x intercepts, so the intercept form is x/2 + y/3 = 1. Multiply both sides by 6: 3x + 2y = 6. 

The slope of the line,m=y-y1/x-x1                             m=3-0/0-2=-3/2 The point slope form is y-y1=m(x-x1) y-0=-3/2(x-2) y=-3/2(x-2) 2y=-3x+6 3x+2y=6 

hope this helps hope i am brainliest