Astorage closet holds twelve boxes stacked upon each other, with each box being 10 inches high. how many feet are there between the top of the third box and the bottom of the tenth box?

Step-by-step explanation:

We just have to count how many boxes is between the top of the third one and the bottom of the tenth box, then we transform from inches to feet.

So, the problem says "from the top of the third box" this means that the inches that matters is form the fourth box. "the bottom of the tenth box" means that it's until the ninth box. In total, there are 6 boxes. If each box is 10 inches high, the total distance would be 6(10 inches) = 60 inches.

Now we have the total distance, we transform it to feet. We know that one feet is 12 inches, using the rule of three we have:

60 inches are equivalent to 5 feet.

Therefore, there are 5 feet between the top of the third box and the bottom of the tenth box.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36