Suppose the population of a small town is 19000 and growing exponentially at 2.3%. how many years until the population until the population reaches 26000

14 years

Step-by-step explanation:

Using the general growth formula

where F is future population, P is present population, n is years and r is rate in percentage.

Substituting 26000 for future population F, 19000 for present population P and 2.3% for rate

Introducing natural logarithms on both sides

n ln 1.023=ln(\frac {26000}{19000})[/tex]

n=(ln 26/19)/(ln 1.023)=13.79351958  years

Rounding off, n=14 years

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5