Garden a has 9 more currant bushes than garden b. if 3 currant bushes are transplanted from garden b to garden a, then garden a will have 1.5 times more currant bushes than garden b. how many currant bushes are in garden a before the transplant?

Garden A has 42 currant bushes before the transplant

Explanation:

Suppose garden A is x and garden B is y

Forming the linear equations

Garden A has  9 more currant bushes than garden B

Therefore

x=y+9 --------(1)

If 3 currant bushes are transplanted from Garden B to Garden A, then Garden A will have 1.5 times more currant bushes than Garden B.

When 3 currant bushes are transplanted then the new equation becomes

x=y+12--------(2)

Further after transplanting

x+3= 1.5y----------(3)

putting the value of y from equation 2 into equation 3

x+3 = 1.5(x-12)

x+3= 1.5x-18

x-1.5x=-18-3

-0.5x=-21

x=42

Hence garden A has 42 currant bushes before the transplant

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.