Ineed on this can someone answer the questions on the picture
on the picture there are three questions on the picture
look at the picture

Step-by-step explanation:

a) height: The length AP is √(3.2² +6.4²) = √51.2 units.

b) base length: The length CD is √(8²+4²) = √80 units.

c) The area is the product of the base and height:

  A = bh = √(80·51.2) = √4096 = 64 . . . . square units.

Comment on this problem

The area of this rhombus is much more easily found using the diagonals. The area of a rhombus is half the product of the lengths of the diagonals. Since those are aligned with the axes, their lengths are easily found as ...

  AC = 16

  BD = 8

Area = (1/2)AC·BD = (1/2)(16)(8) = 64 . . . square units

Obviously, the problem is not about the area of the rhombus. Rather, it is about finding the lengths of line segments from their coordinates.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.