List the first five terms of each sequence.
an+1 = an + 6, where a1 = 11 for n ≥ 1

17 , 23 , 29 , 35 and 41

Step-by-step explanation:

Given : = + 6 , where n≥1 , it means n can pick values from 1 and above

When n = 1 , the sequence becomes

= + 6

And it has been given that = 11 , substitute this value into the sequence, that is

= 11 + 6

= 17

Also , when n = 2 , the sequence becomes

= + 6

substituting the value of , we have

= 17 + 6 = 23

When n = 3 , the sequence becomes

= + 6

substituting the value of , we have

= 23 + 6 = 29

When n = 4 , the sequence becomes

[ = + 6 , substituting the value of , we have

= 29 + 6 = 35

And finally , when n = 5 , the sequence becomes

= + 6

Substituting the value of , we have

= 35 + 6 = 41

Therefore , the first five terms are : 17 , 23 , 29 ,35 and 41

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step-by-step explanation:

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: