27. suppose the hare runs 600 inches per second and the tortoise runs
3 inches per second. when...
Mathematics, 23.10.2019 07:50, dantelin123
27. suppose the hare runs 600 inches per second and the tortoise runs
3 inches per second. when the hare wakes up, the tortoise is 1000 feet (or 12.000 inches) ahead. which equation represents when the hare will catch up with the tortoise? (hint: if t represents time in seconds
then 3t is the distance in inches the tortoise can travel in t seconds.)
a. 3t = 600t + 12,000
b. 600t = 3t + 12,000
c. 3t - 12,000 = 600t d . 600t = 12,000
also show steps.
Answers: 1
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