the proof shows that abcd is a rhombus. which of the following is the missing reason?
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Mathematics, 23.10.2019 05:00, deadlydemon0500
the proof shows that abcd is a rhombus. which of the following is the missing reason?
Answers: 3
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Mathematics, 21.06.2019 22:10, ansonferns983
Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.
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