How to solve 45y to the second power plus 15y minus 10 ?

Either y = or, y =

Step-by-step explanation:

We have to solve the following quadratic equation  

45y² + 15y - 10 =0

Now, dividing both sides with 5 we get, 9y² + 3y -2 =0

Hence, to solve the above equation we have to factorize the left-hand part of the equation.

So, 9y² + 3y - 2 =0

⇒ 9y² +6y -3y -2 =0

⇒ (3y +2) (3y -1 ) =0

⇒ Either (3y +2) =0 or (3y -1) =0

⇒ Either y = or, y = (Answer)

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!