Kayson is looking at two buildings, building a and building b, at an angle of elevation of 73°. building a is 30 feet away, and building b is 35 feet away. which building is taller and by approximately how many feet?

The Building B is taller than Building A and by 16.354 feet ≈16 feet.

Step-by-step explanation:

Kayson is looking at building A at an angle of elevation of 73° and building A is 30 feet away from him.

So, if the height of the building A is x feet, then we can write,  

tan 73°=x/30, ⇒x =30 tan73° =98.125 feet.

Again, Kayson is looking at building B at an angle of elevation of 73° and building B is 35 feet away from him.

So, if the height of the building B is y feet, then we can write,

tan 73° =y/35, ⇒ y= 35 tan73° = 114.479 feet.

Therefore, Building B is taller than Building A and by (114.479-98.125) =16.354 feet ≈16 feet. (Answer)

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi