94. solve each equation. express your answer as a logarithm, and then approximate the solution to the nearest thousandth.
d. 300 e 0.4t = 900

t = ln 3/0.4 (answer as a logarithm)

t =  2.747 (answer to the nearest thousandth)

Step-by-step explanation:

300 = 900

= 900/300

= 3

ln () = ln 3

0.4t * ln e = ln 3

0.4t = ln 3

t = ln 3/0.4 (answer as a logarithm)

t =  2.747 (answer to the nearest thousandth)

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

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step-by-step explanation: